- Forums
- Physics
- Special and General Relativity
- I
- Thread starterTio Barnabe
- Start date
- Tags
- ExistenceVectors
In summary, the conversation discusses the concept of Killing vectors and how they represent symmetries in the metric. It is noted that if the metric has no symmetries, then there are no Killing vectors. The question is raised whether general relativity allows for spaces where the Killing equation cannot be satisfied. The concept of inner product is also briefly discussed, with clarification requested on its usage. However, it is pointed out that points in a manifold are not vectors and therefore the notation used in the conversation is incorrect.
- #1
Tio Barnabe
By requiring the inner product in two points ##x## and ##x'## having metrics ##g## and ##g'## to be invariant, i.e. ##g'(x') = g(x)##, one is lead to the Killing equation. Does general relativity forbiddes spaces where the Killing equation cannot be satisfied?
It seems obvious that we want conserved quantities in our theories. But, is there a way around in which we can consider a space-time having no Killing Vectors at all?
Physics news on Phys.org
- #2
PeroK
Science Advisor
Homework Helper
Insights Author
Gold Member
2023 Award
- 27,257
- 18,675
Tio Barnabe said:
By requiring the inner product in two points ##x## and ##x'## having metrics ##g## and ##g'## to be invariant, i.e. ##g'(x') = g(x)##, one is lead to the Killing equation. Does general relativity forbiddes spaces where the Killing equation cannot be satisfied?
It seems obvious that we want conserved quantities in our theories. But, is there a way around in which we can consider a space-time having no Killing Vectors at all?
A Killing vector represents a symmetry in the metric. If the metric has no symmetries then there are no Killing vectors.
Although the gravity affecting the Earth's solar orbit is nearly symmetric, if you include all the factors, then at a certain level of accuracy it won't be symmetric at all.
- #3
PeterDonis
Mentor
Insights Author
- 45,704
- 22,687
Tio Barnabe said:
By requiring the inner product in two points ##x## and ##x'## having metrics ##g## and ##g'## to be invariant, i.e.##g'(x') = g(x)##, one is lead to the Killing equation.
How so?
Tio Barnabe said:
Does general relativity forbiddes spaces where the Killing equation cannot be satisfied?
Certainly not.
- #4
PAllen
Science Advisor
- 9,180
- 2,412
Inner product, so far as I know, is an operation on two vectors producing a scalar. Your usage does not appear to jive with this. Please clarify
- #5
Tio Barnabe
PeterDonis said:
How so?
PAllen said:
Please clarify
I just considered that the two points ##x## and ##x'## were vectors themselves, in which my notation ##g(x)## means the inner product of ##x## with itself (similarly for ##g'(x')##). Couldn't I do that?
- #6
PAllen
Science Advisor
- 9,180
- 2,412
Tio Barnabe said:
I just considered that the two points ##x## and ##x'## were vectors themselves, in which my notation ##g(x)## means the inner product of ##x## with itself (similarly for ##g'(x')##). Couldn't I do that?
Points in a manifold are not vectors. Vectors live in the tangent space to a manifold at a given point. In flat space, position vectors do happen to form a vector space, but not if there is any curvature. Also, for flat space, you can choose to treat the space as it’s own tangent space, but again you cannot if there is any curvature.
- #7
PeterDonis
Mentor
Insights Author
- 45,704
- 22,687
Tio Barnabe said:
I just considered that the two points ##x## and ##x'## were vectors themselves
Which, as @PAllen has pointed out, is incorrect. So this entire thread appears to be based on a mistaken premise in your OP.
Thread closed.
1. What is a Killing vector?
A Killing vector is a vector field that satisfies the Killing equation, which is a differential equation that describes the invariance of a metric tensor under a specific transformation. In simpler terms, it is a vector that preserves the length and angle of other vectors in a given space.
2. What is the significance of Killing vectors in physics?
Killing vectors are important in physics because they represent symmetries in a physical system. These symmetries can be used to simplify and solve equations in fields such as general relativity and quantum mechanics.
3. How are Killing vectors related to conserved quantities?
Killing vectors are related to conserved quantities through Noether's theorem, which states that for every continuous symmetry in a physical system, there exists a conserved quantity. In other words, for every Killing vector, there is a corresponding conserved quantity.
4. Can a space have more than one Killing vector?
Yes, a space can have multiple Killing vectors. In fact, a space with more than one Killing vector is considered to have a higher degree of symmetry, making it easier to analyze and solve equations in that space.
5. How are Killing vectors used in black hole physics?
Killing vectors are essential in the study of black holes, as they can be used to define the event horizon and calculate the conserved quantities associated with the black hole, such as its mass, angular momentum, and charge. They are also used in the study of black hole thermodynamics and the behavior of particles near the event horizon.
Similar threads
IInvariant Mass-Energy in FRW Spacetime
- Special and General Relativity
- Replies
- 19
- Views
- 1K
IA question about metric compatibility equation
- Special and General Relativity
2
- Replies
- 62
- Views
- 3K
AUnderstanding killing vectors and transformations of metric
- Special and General Relativity
2
- Replies
- 45
- Views
- 3K
I
- Special and General Relativity
- Replies
- 1
- Views
- 2K
IMinkowski Spacetime KVF Symmetries
- Special and General Relativity
- Replies
- 32
- Views
- 1K
IIs Zero Curvature Space Equivalent to Flat Space in General Relativity?
- Special and General Relativity
2
- Replies
- 35
- Views
- 3K
IConservation of energy in general relativity
- Special and General Relativity
2
- Replies
- 42
- Views
- 4K
A
- Special and General Relativity
- Replies
- 8
- Views
- 2K
IParallel transport vs Lie dragging along a Killing vector field
- Special and General Relativity
- Replies
- 20
- Views
- 2K
A
- Special and General Relativity
- Replies
- 7
- Views
- 924
- Forums
- Physics
- Special and General Relativity